Answer:
(a) The area of space shuttle is [tex]2.07\times 10^{-9} km^2[/tex].
(b) $10.427 is the cost of the patch.
Explanation:
Area of the patch of the space shuttle = [tex]20.7 cm^2[/tex]
a) 1 cm = 0.00001 km
[tex]1 cm^2= (0.00001 km)^2=10^{-10}km^2[/tex]
[tex]20.7 cm^2=20.7\times 10^{-10}km^2=2.07\times 10^{-9} km^2[/tex]
b) 1 cm = 0.393701 inch
[tex]1 cm ^2=0.1550 inch^2[/tex]
[tex]20.7 cm^2=20.7\times 0.1550 inch^2=3.2085 inch^2[/tex]
Cost of patching area = [tex]\$3.25/inch^2[/tex]
Cost of patching [tex]3.2085 inch^2[/tex] are:
[tex]\$3.25/inch^2\times 3.2085 inch^2=\$10.427[/tex]
