Answer:
-0.715
Step-by-step explanation:
Take the log to the base 6, then apply your change-of-base formula.
[tex]6^{x+2}=10\\\\x+2=\log_6{10}\\\\x=\log_6{(10)}-2\\\\x=\dfrac{\log{10}}{\log{6}}-2\\\\x=\dfrac{1}{\log{6}}-2\approx -0.714903\\\\\boxed{x\approx -0.715}[/tex]
