Respuesta :
Answer:
For a: The chemical formula for Iron (III) sulfide is [tex]Fe_2S_3[/tex]
For b: The chemical formula for mercury (II) nitrate is [tex]Hg(NO_3)_2[/tex]
For c: The chemical formula for potassium sulfite is [tex]K_2SO_3[/tex]
Explanation:
All the given compounds are ionic compounds. This means that between the atoms complete sharing of electrons takes place.
- For a:
Iron is the 26th element of periodic table having electronic configuration of [tex][Ar]3d^64s^2[/tex].
To form [tex]Fe^{3+}[/tex] ion, this element will loose 3 electrons.
Sulfur is the 16th element of periodic table having electronic configuration of [tex][Ne]3s^23p^4[/tex].
To form [tex]S^{2-}[/tex] ion, this element will gain 2 electrons.
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the chemical formula for Iron (III) sulfide is [tex]Fe_2S_3[/tex]
- For b:
Mercury is the 80th element of periodic table having electronic configuration of [tex][Xe]4f^{14}5d^{10}6s^2[/tex].
To form [tex]Hg^{2+}[/tex] ion, this element will loose 2 electrons.
Nitrate ion is a polyatomic ion having chemical formula of [tex]NO_3^{-}[/tex]
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the chemical formula for mercury (II) nitrate is [tex]Hg(NO_3)_2[/tex]
- For c:
Potassium is the 19th element of periodic table having electronic configuration of [tex][Ar]4s^1[/tex].
To form [tex]K^{+}[/tex] ion, this element will loose 1 electron.
Sulfite ion is a polyatomic ion having chemical formula of [tex]SO_3^{2-}[/tex]
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the chemical formula for potassium sulfite is [tex]K_2SO_3[/tex]
