Answer:
Let yellow=G and green=g; round=R and wrinkled=r
A: GgRR
B: GGRR
C: GgRr
Explanation:
The question tells us that plants A,B and C are all crossed with the same green, wrinkled pea plant, thus we know that this is a test cross and the green, wrinkled plant is completely recessive (ggrr). Therefore, we know that yellow is dominant over green and round is dominant over wrinkled.
When plant A was put through the test cross all the peas were round, but half the peas were yellow and half were green. From this we can deduce that plant A must have been heterozygous for the yellow trait and homozygous for the round trait.
When plant B was put through the test cross all the peas were yellow and round. From this we can deduce that plant B must have been homozygous for the yellow trait and homozygous for the round trait.
When plant C was put through the test cross every trait was shown in the peas. We can then deduce that plant C must have been heterozygous for the yellow trait and heterozygous for the round trait.