Answer:
678 mL.
Explanation:
The balanced reaction between calcium chloride and silver nitrate is shown in figure.
As shown in the equation , each mole of aqueous calcium chloride will rect with two moles of silver nitrate.
The moles of calcium chloride taken = molarity X volume (L)
= 0.37X0.33 = 0.122 mol
the moles of silver nitrate required = 2 X 0.122 = 0.244 mol
the volume of silver chloride required = [tex]\frac{mol}{M}[/tex]
M = 0.36 M
mol = 0.244
Putting values
volume = 0.678 L = 678 mL.
