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Ethane and acetylene are two gaseous hydrocarbons. Chemical analyses show that in one sample of ethane, 2.65 g of carbon are combined with 0.665 g of hydrogen, and in one sample of acetylene, 4.56 g of carbon are combined with 0.383 g of hydrogen. (a) Are these results consistent with the law of multiple proportions? (b) Write reasonable molecular formulas for these compounds.

Respuesta :

Answer:

Explanation:

in ethane :-

2.65 g of carbon reacts with 0.665 g of hydrogen

1 g of carbon reacts with .665/2.65 = 0.2509 g of hydrogen

now in the acetylene

4.56 g of carbon reacts with 0.383 g of hydrogen

1 g of carbon reacts with 0.383/4.56= 0.08399 g of hydrogen.

ratio of hydrogen reacting with 1 g of carbon is aas follows

ratio of hydrogen =0 .2509/ 0.08399 =2.98 or 3/1 approx which is a ratio of small whole nos.

b) . CH₃ - Ethane

CH- Acetylene.