Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=[tex]2C2*7C3[/tex]=35
Total no of ways = [tex]9C5[/tex]=126
= [tex]\frac{2C2*7C3}{9C5}[/tex]=[tex]\frac{35}{126} =\frac{5}{18}[/tex]
