Answer : The balanced redox reaction will be,
[tex]6Cl^-(aq)+2NO_3^-(aq)+8H^+(aq)\rightarrow 2NO(g)+3Cl_2(g)+4H_2O(l)[/tex]
Explanation :
The given chemical equation is,
[tex]Cl^-(aq)+NO_3^-(aq)\rightarrow NO(g)+Cl_2(g)[/tex]
In the half reaction method, the number of atoms in each half reaction and number of electrons must be balanced.
The half reactions in the acidic medium are :
Reduction : [tex]NO_3^-(aq)+4H^+(aq)+3e^-\rightarrow NO(g)+2H_2O(l)[/tex] ......(1)
Oxidation : [tex]2Cl^-(aq)\rightarrow Cl_2(g)+2e^-[/tex] .......(2)
Now multiply the equation (1) by 2 and equation (2) by 3 then added both equation, we get the balanced redox reaction.
Thus, the balanced redox reaction will be,
[tex]6Cl^-(aq)+2NO_3^-(aq)+8H^+(aq)\rightarrow 2NO(g)+3Cl_2(g)+4H_2O(l)[/tex]
