Respuesta :
Answer:
axis of symmetry is [tex]x=\frac{-9}{2}[/tex].
The ordered pair of the vertex is [tex](\frac{-9}{2},\frac{-145}{4})[/tex].
Step-by-step explanation:
Your function is a quadratic.
Compare [tex]x^2+9x-16[/tex] to [tex]ax^2+bx+c[/tex].
You should see that [tex]a=1,b=9,c=-16[/tex].
The x-coordinate of the vertex or the axis of symmetry since the axis symmetry goes through the vertex can be found by computing [tex]\frac{-b}{2a}[/tex].
So here we go!
The axis of symmetry is [tex]x=\frac{-9}{2(1)}=\frac{-9}{2}[/tex].
When you write your axis of symmetry be sure to write it as an equation.
That is the axis of symmetry is [tex]x=\frac{-9}{2}[/tex].
Now that was also the x-coordinate of your vertex. To find the corresponding y-coordinate of the vertex, plug your value for [tex]x[/tex] into
[tex]y=x^2+9x-16[/tex].
[tex]y=(\frac{-9}{2})^2+9(\frac{-9}{2})-16[/tex]
Put into calculator:
[tex]y=\frac{-145}{4}[/tex] when [tex]x=\frac{-9}{2}[/tex]
The ordered pair of the vertex is [tex](\frac{-9}{2},\frac{-145}{4})[/tex].
Answer:
Vertex: [tex](h,k)\rightarrow(-4.5,-36.25)[/tex]
Axis of symmetry: [tex]x=-4.5[/tex]
Step-by-step explanation:
Finding the Axis of Symmetry:
First I'll find the axis of symmetry. This formula lets us find the a.o.s: [tex]x=\frac{-b}{2a}[/tex].
In [tex]x^2+9x-16[/tex], the values of a, b, and c are:
- a: 1
- b: 9
- c: -16
We only need a and b to find the axis of symmetry. Substitute these values into the formula.
- [tex]x=\frac{-(9)}{2(1)}[/tex]
Simplify this fraction.
- [tex]x=\frac{-9}{2} =-4.5[/tex]
The axis of symmetry of this quadratic function is x = -4.5.
Finding the Vertex:
Now to find the vertex, we have to take into account that this quadratic is in standard form, making it a little harder. We have to convert this function into vertex form.
Start by changing f(x) to 'y' and adding 16 to both sides.
- [tex]y+16=x^2+9x[/tex]
Use the completing the square formula: [tex](\frac{b}{2} )^2[/tex]
- [tex](\frac{9}{2} )^2=20.25[/tex]
Keep the balance by adding 20.25 on the left side and adding it on the right side of the equation.
- [tex]y+16+20.25=x^2+9x+20.25[/tex]
Combine like terms.
- [tex]y+36.25=x^2+9x+20.25[/tex]
Factor the right side of the equation. Ask yourself, "What two numbers multiply to 20.25 (c) and add up to 9 (b)?" These two numbers are 4.5 and 4.5. Rewrite the right side with factors.
- [tex]y+36.25=(x+4.5)(x+4.5)[/tex]
- [tex]y+36.25=(x+4.5)^2[/tex]
Isolate y by subtracting 36.25 from both sides of the equation.
- [tex]y=(x+4.5)^2-36.25[/tex]
Now this quadratic function is in vertex form, making it super simple to find the vertex using [tex](h, k)[/tex].
Vertex form of a quadratic is:
- [tex]y=a(x-h)^2+k[/tex]
Compare [tex]y=(x+4.5)^2-36.25[/tex] with the original vertex form and find where h and k are. Those are the x (h) and y (k) values of the vertex.
Since the original vertex form has x - h, the h value in [tex]y=(x+4.5)^2-36.25[/tex] would be a negative since two negatives make a positive. The k value would stay "normal"---negative would mean it is a negative and positive would mean it is a positive number.
Therefore the h value is -4.5, and the k value is -36.25.
The ordered pair of the vertex is [tex](-4.5, -36.25)[/tex].