Respuesta :

absor201

Answer:

4 and 11

Step-by-step explanation:

Lets call the smallest n

And the other one n+7

Then,

n.(n+7)=44

n²+7n=44

Subtract 44 from both sides.

n²+7n-44=44-44

n²+7n-44=0

Factorize the equation.

n²+11n-4n-44=0

n(n+11)-4(n+11)=0

(n+11)(n-4)=0

n+11=0 , n-4=0

n=-11 , n=4

n=4 is the only positive solution, so the numbers are:

4 and 11....

alinakincsem

Answer:

The two integers are: 4 and 11.

Step-by-step explanation:

We are given that one positive integer is 7 less than another. Given that the product of two integers is 44, we are to find the integers.

Assuming [tex]x[/tex] to be one positive integer and [tex]y[/tex] to be the other, we can write it as:

[tex]x=y-7[/tex] --- (1)

[tex]x.y=44[/tex] --- (2)

Substituting x from (1) in (2):

[tex](y-7).y=44[/tex]

[tex]y^2-7y-44=0\\\\y^2-11y+4y-44=0\\\\y(y-11)+4(y-11)[/tex]

y = 11

Substituting y = 11 in (1) to find x:

[tex]x=11-7[/tex]

x = 4

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