If the temperature of 9.3 L of a gas at 6.5 ºC falls by 6.1 Cº, what is the new volume of the gas if the pressure is constant?

Select one:
a. 9.10
b. 9.29
c. 0.0133
d. 45.74

Respuesta :

I believe 9.29 for temperature

Answer:

b. 9.29 L is the new volume of the gas if the pressure is constant.

Explanation:

As per Charles’s law  

At constant pressure for a given amount of a gas,

Volume is directly proportional to its temperature.

Thus the expression is [tex]V \propto T[/tex]

[tex]\frac {V}{T} = k[/tex] where k is a constant  

When there is a change in the volume and temperature the expression will be

[tex]\frac {V_1}{T_1} = \frac {V_2}{T_2}[/tex]

where [tex]V_1[/tex] and [tex]T_1[/tex] are the initial volume and initial temperature and [tex]V_2[/tex] and [tex]T_2[/tex] are the final volume and temperature.

Plugging in the values given

[tex]\frac {(9.3L)}{(279.5K)}=\frac {V_2}{(279.1K)}[/tex]

[tex]V_2=\frac {(9.3L\times279.1K)}{279.5K} \\\\=9.29L[/tex]

(Answer)