Sue used the following method to convert 5 g/gal to oz/m^3.

((5 g) / (1 gal)) x ((1 gal/ (0.00378541 m^3)) x ((1 m^3) / (28.3495 g)) = 45.59 oz/m^3

(1 gal = 0.00378541 m^3 and 1 oz = 28.3495 g)

What is the error in Sue’s conversion method?

A. 0.00378541 m^3 should be written as 0.00378541 gal.

B. 28.3495 g should be written as 28.3495 oz.

C. 5 g should be written as 5 oz.

D. 1 m^3 should be written as 1 oz.

Question

contestada

Respuesta :

Tringa0 Tringa0 · Answer 1 · 2019-08-13T11:08:21+02:00

Answer:

The correct answer is option D.

Explanation:

5 g/gal to [tex]oz/m^3[/tex]

[tex]1 gal = 0.00378541 m^3[/tex]

[tex]1 oz = 28.3495 g[/tex]

[tex]\frac{5g}{1 gal}\times \frac{1 gal}{0.00378541 m^3}\times \frac{1 m^3}{28.3495 g}=45.59 [/tex] unitless (not possible)

Common unit present in denominator and numerator will get cancelled.

[tex]\frac{5g}{1 gal}\times \frac{1 gal}{0.00378541 m^3}\times \frac{1 oz}{28.3495 g}=46.59 oz/m^3[/tex]

The error in the conversion was instead of [tex]1 m^3[/tex] 1 oz should be written.

virtuematane virtuematane · Answer 2 · 2021-12-21T14:43:37+01:00

The correct answer is D.

The conversion of 5 g/gal to oz/m^3 is as follows:-

Given:-1 gal = 0.00378541 m^3

1 oz = 28.3495 g

Accoring to sue:-

[tex]\frac{5\ g}{1\ gal} \times\frac{1\ gal}{0.00378541\ m^{3} }\times\frac{1\ m^{3}}{28.3495\ g} \\=45.59[/tex]

Common units present in numerator and denominator will get canceled.

The correct conversion is as follows:-

[tex]\frac{5\ g}{1\ gal} \times\frac{1\ gal}{0.00378541\ m^{3} }\times\frac{1\ oz}{28.3495\ g} \\=45.59\ oz/m^{3}[/tex]

The error in the conversion was instead of [tex]1\ m^{3}[/tex], 1 oz should be written.

To know more about:-

https://brainly.com/question/13060762