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After traveling steadily at 400 meters above a shipwrecked hull, a submerged vessel starts to descend when its ground distance
from the hull is 7 kilometers. What is the angle of depression for this part of the travel?
Select one
O a 1.00
6.327
C 86.73
d. 88.00

Respuesta :

Answer:

im trying to find this answer too dont worry :(

Step-by-step explanation:

I dont know

Answer:

Option B, [tex]3.27[/tex]

Step-by-step explanation:

Given -

The submerged vessel travel horizontal distance above the shipwrecked hull

[tex]= 400[/tex]

[tex]= 0.4[/tex] kilometers

The vertical distance from the the shipwrecked hull to the ground is equal to [tex]7[/tex] kilometers

There forms a right angled triangle with

Base [tex]= 7[/tex] kilometer

Perpendicular [tex]=[/tex] 0.4 kilometer

Tan (angle) [tex]= \frac{Perpendicular}{Base}[/tex]

Substituting the given values we get -

Angle of depression

[tex]= tan^{-1}(\frac{0.4}{7})\\= 3.27[/tex]

Hence, option B is correct.

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