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Constants A capacitor is connected across an ac source that has voltage amplitude 59 0 V and frequency 77 0 Hz Part C What is the capacitance C of the capacitor if the current amplitude is 5.05 A Express your answer with the appropriate units. C 0.17-10F Submit Previous Answers

Respuesta :

Answer:

[tex]C = 1.77 \times 10^{-4} F[/tex]

Explanation:

As we know that in AC circuit we have

[tex]V = i x_c[/tex]

here we have

V = 59 V

i = 5.05 A

so we will have

[tex]x_c = \frac{59}{5.05}[/tex]

[tex]x_c = 11.68 ohm[/tex]

also we know that

[tex]x_c = \frac{1}{\omega C}[/tex]

here we will have

[tex]11.68 = \frac{1}{(2\pi 77)C}[/tex]

[tex]C = 1.77 \times 10^{-4} F[/tex]

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