Answer:
[tex]5.32\cdot 10^4 g[/tex]
Explanation:
First of all, we need to find the volume of the room, which is given by
[tex]V=2.50 m \cdot 5.50 m \cdot 3.00 m =41.3 m^3[/tex]
Now we can find the mass of the air by using
[tex]m=dV[/tex]
where
[tex]d=1.29 g/dm^3[/tex] is the density of the air
[tex]V=41.3 m^3 = 41,300 dm^3[/tex] is the volume of the room
Substituting,
[tex]m=(1.29)(41300)=5.32\cdot 10^4 g[/tex]
