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(CO 3) A survey indicates that shoppers spend an average of 22 minutes with a standard deviation of 8 minutes in your store and that these times are normally distributed. Find the probability that a randomly selected shopper will spend less than 20 minutes in the store. 0.40 0.50 0.60 0.22

Respuesta :

JeanaShupp

Answer: 0.60

Step-by-step explanation:

Given: Mean : [tex]\mu = 22\text{ minutes}[/tex]

Standard deviation : [tex]\sigma = 8\text{ minutes}[/tex]

The formula to calculate z is given by :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x= 20 minutes

[tex]z=\dfrac{22-20}{8}=0.25[/tex]

The P Value =[tex]P(z<0.25)= 0.5987063\approx0.60[/tex]

Hence, the probability that a randomly selected shopper will spend less than 20 minutes in the store= 0.60

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