Respuesta :
Each pencil box usually contains same amount of pencils. In given context the number of pencils in five boxes is 10 pencils.
How to decide the number of containment of items?
Suppose that its given that 'a' boxes contains 'b' items, then, assuming that each box contains 'x' items, then
[tex]x + x + ... + x \text{ (a times)} = b\\\\x \times a = b\\\\x = \dfrac{b}{a}[/tex]
Thus, there are 'b/a' items contained in each box.
Since there are six pencils in three boxes, let there are 'x' pencils in one box, then we have:
[tex]x + x + x = 6\\3 \times x = 6\\\\\text{Dividing both sides by 3}\\\\x = \dfrac{6}{3} = 2[/tex]
Thus, there are 2 pencils in each pencil box.
Thus, for 5 boxes, we get [tex]2 \times 5 = 10[/tex] pencils.
Thus,
In given context the number of pencils in five boxes is 10 pencils.
Learn more about division here:
https://brainly.com/question/2689177