Milan uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below:

Number on the Cube Number of Times Rolled
1 10
2 8
3 33
4 29
5 11
6 9

Heads Tails
29 71

Using Milan's simulation, what is the probability of rolling a 5 on the number cube and the coin landing on tails?

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pleasehelpally pleasehelpally · Answer 1 · 2019-05-15T22:30:03+02:00

rolling a 5= 11/100

getting tails=71/29

i’m pretty sure you times the fractions together to get an overall probability

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lidaralbany lidaralbany · Answer 2 · 2019-07-16T10:33:14+02:00

The probability of rolling a 5 on number cube and tail on coin is:

[tex]P(A\bigcap B)=\dfrac{781}{10000}[/tex]

or

[tex]P(A\bigcap B)=0.0781[/tex]

Let A denote the event of rolling a 5 on the number cube.

and B denote the event of coin landing on tails.

Let P denote the probability of an event.

Also, event A is independent of event B.

( Since, both the events are not affected by happening of each other )

We are asked to find the probability: P(A∩B)

We know that:

[tex]P(A\bigcap B)=P(A)\cdot P(B)[/tex]

( Since, both the events are independent )

Also,

[tex]P(A)=\dfrac{11}{100}[/tex]

( Since, 5 occurs 11 times out of a total of 100 times on the number cube )

and

[tex]P(B)=\dfrac{71}{100}[/tex]

Hence, we have:

[tex]P(A\bigcap B)=\dfrac{11}{100}\times \dfrac{71}{100}[/tex]

i.e.

[tex]P(A\bigcap B)=\dfrac{781}{10000}[/tex]

i.e.

[tex]P(A\bigcap B)=0.0781[/tex]