Respuesta :
The length of diagonal EK is sqrt(5^2 + 4^2) ≈ 6.403m
Hence perimeter = 2*(12 + 6.403) → 36.8 m (to the nearest tenth of a metre)
The perimeter of the cross-section is 36.8 m.
Calculations and Parameters:
Given that the length of diagonal EK is
[tex]\sqrt{(5^2 + 4^2) }[/tex]
≈ 6.403m
Thus, the perimeter would be
2*(12 + 6.403)
→ 36.8 m.
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