Answer:
The average rate of change of f(t) from t = 3 seconds to t = 5 seconds is -80 feet per second.
Step-by-step explanation:
The function that models the height of the ball is:
[tex]f(t)=-16t^2+48t=160[/tex]
At t=3, [tex]f(3)=-16(3)^2+48(3)+160=160[/tex]
At t=5, [tex]f(5)=-16(5)^2+48(5)+160=0[/tex]
The average rate of change is simply the slope of the secant line connecting.
[tex](3,f(3))[/tex] and [tex](5,f(5))[/tex].
The average rate of change
[tex]=\frac{f(3)-f(5)}{3-5}[/tex]
[tex]=\frac{160-0}{-2}[/tex]
[tex]=-80fts^{-1}[/tex]
