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racquetball strikes a wall with a speed of 30 m/s and rebounds in the opposite direction with a speed of 26 m/s. The collision takes 20 ms. What is the average acceleration of the ball during the collision with the wall?

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Respuesta :

musiclover10045

Vo = 30 m/s Vf = 26 m/s, t = 20ms = 0.02s

A = Vo + Vf / t

A = 30 + 26 / 0.02

A = 56 /0.02

A = 2800 m/s^2

onyebuchinnaji

The  average acceleration of the racket is 2,800 m/s²

The given parameters include;

initial speed of the racket, u = 30 m/s

recoil velocity of the racket, v = 26 m/s

time of collision, t = 20 m/s

To find:

  • the average acceleration of the racket

Let the backward or recoil velocity be in negative direction

The average acceleration of the racket is calculated as;

[tex]average \ acceleration \ =\frac{\Delta \ velocity}{\Delta \ time} = \frac{v - u}{t} \\\\average \ acceleration \ = \frac{-26 - 30}{20 \times 10^{-3}}= \frac{-56}{20 \times 10^{-3}} = -2,8 00\ m/s^2\\\\magnitude \ of \ average \ acceleration = 2,800 \ m/s^2[/tex]

Thus, the  average acceleration of the racket is 2,800 m/s²

Learn more here: https://brainly.com/question/15270488

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