Leave your answer in simplest radical form

Answer:
[tex]|KL|=7\sqrt{2}[/tex]
Step-by-step explanation:
The given triangle is a right triangle.
The m<K=45 degrees.
This means the measure of <L is also 45 degrees.
This implies that;
|LM|=|KM|=7 units.
From the Pythagoras Theorem;
[tex]|KL|^2=|LM|^2+|KM|^2[/tex]
[tex]|KL|^2=7^2+7^2[/tex]
[tex]|KL|^2=2(7^2)[/tex]
[tex]|KL|=\sqrt{2(7^2)}[/tex]
[tex]|KL|=7\sqrt{2}[/tex]
Option C is correct.
The answer is:
The third option,
[tex]KL=7\sqrt{2}[/tex]
Since we are working with a right triangle, we can use the following identity:
[tex]Sin(\alpha)=\frac{y}{hypothenuse}[/tex]
We are given:
[tex]\alpha =45\°\\LM=y=7[/tex]
[tex]hypothenuse=KL[/tex]
Then, substituting and solving we have:
[tex]Sin(45\°)=\frac{7}{hypothenuse}[/tex]
[tex]Hypothenuse=KL=\frac{y}{Sin(45\°)}=\frac{7}{\frac{\sqrt{2} }{2} } \\\\Hypothenuse=KL=7\sqrt{2}[/tex]
Hence, the answer is the third option,
[tex]KL=7\sqrt{2}[/tex]
Have a nice day!