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A field with an area of 2880 ft^2 has the shape of a rectangle, whose length is 12 ft larger than its width. Find the dimensions of this field.

Respuesta :

kudzordzifrancis

ANSWER

w=48,l=60

EXPLANATION

Let the width of the field be, w , then,

the length of the field will be:

[tex]l = 12 + w[/tex]

The area of a rectangle is

[tex]Area = lw[/tex]

This implies that:

[tex]w(12 + w) = 2880[/tex]

Expand

[tex] {w}^{2} + 12w = 2880[/tex]

[tex] {w}^{2} + 12w - 2880 = 0[/tex]

[tex](x + 60)(x - 48) = 0[/tex]

This implies that,

[tex]w = - 60 \: w = 48[/tex]

The dimensions are positive, the width is 48 and the length is 12+48=60

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