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Answer:

How about this?

Explanation:

(1) Halogenation of an alkane

Reaction with Br₂ in the presence of UV light to give bromocyclopentane.

(2) Dehydrohalogenation

Reaction with hot alcoholic KOH to give cyclopentene.

(3) Allylic bromination

Reaction with N-bromosuccinimide and a drop of HBr(aq) gives

3-bromocyclopentene.

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A three-step synthesis of 3-bromocyclopentene from cyclopentane is as follows:

(1) Halogenation of an alkane

(2) Dehydrohalogenation

(3) Allylic bromination

What is a halogenation reaction?

Generally, halogenation is the reaction of a halogen with an alkane in which the introduction of halogen atoms occurs into the organic molecule by an addition reaction or by a substitution reaction.

(1) Halogenation of an alkane

  • Halogenation of an alkane produces a hydrocarbon derivative in which one or more halogen atoms have been substituted for hydrogen atoms.
  • Reaction with Br₂ in the presence of UV light to give bromocyclopentane.

(2) Dehydrohalogenation

  • Dehydrohalogenation is an elimination reaction which removes a hydrogen halide from a substrate.
  • Reaction with hot alcoholic KOH to give cyclopentene.

(3) Allylic bromination

  • NBS reacts with trace amounts of HBr to produce a low enough concentration of bromine to facilitate the allylic bromination reaction.
  • Reaction with N-bromosuccinimide and a drop of HBr(aq) gives 3-bromocyclopentene.

Hence, the three steps are halogenation, dehydrohalogenation, and allylic bromination.

Learn more about the halogenation reaction here:

https://brainly.com/question/14532845

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