For this case we have by definition, that the total surface area of a regular pyramid with a square base is given by:
[tex]SA = \frac {1} {2} p * S + A_ {b}[/tex]
Where:
p: It is the perimeter of the base
S: It's the inclination
[tex]A_ {b}:[/tex] It is the area of the base
Substituting:
[tex]A_ {b} = 7 ^ 2 = 49units ^ 2\\p = 7 + 7 + 7 + 7 = 28units\\S = 10units\\SA = \frac {1} {2} 28 * 10 + 49\\SA = 140 + 49\\SA = 189 \ units ^ 2[/tex]
ANswer:
Option B
