For this case we have by definition, that the volume of a square base pyramid is given by:
[tex]V = \frac {1} {3} * L ^ 2 * h[/tex]
Where:
L: It's the side of the base (square side)
h: It's the height of the pyramid
Substituting:
[tex]L = 6 \ ft\\h = 10 \ ft[/tex]
[tex]V = \frac {1} {3} * (6) ^ 2 * 10\\V = \frac {1} {3} * 36 * 10\\V = 120 \ ft ^ 3[/tex]
Answer:
[tex]V = 120 \ ft ^ 3[/tex]
