ANSWER
A. (2,-2)
EXPLANATION
The given system of equations is:
[tex]6x + 2y = 8...(1)[/tex]
and
[tex]12x + y = 22...(2)[/tex]
Divide through the first equation by 2,
[tex] \implies \: 3x + y = 4...(3)[/tex]
Subtract equation (3) from equation (2) to eliminate y.
[tex] \implies \: 12x - 3x = 22 - 4[/tex]
[tex]9x = 18[/tex]
Divide both sides by 9.
[tex]x = \frac{18}{9} [/tex]
[tex]x = 2[/tex]
Put x=2 into one of the equations, say equation (3) to find y,
[tex]3(2) + y = 4[/tex]
[tex]6 + y = 4[/tex]
[tex]y = 4 - 6[/tex]
[tex]y = - 2[/tex]
The solution is (2,-2).
