let two numbers be a and b
then
by question
case I
a=4b...........(1)
case II
a+b=20
4b+b=20 [from eq.1]
5b=20
b=4
then in eq.1
a=4×4
a=16
the rquired two numbers are 4 and 16.
ANSWER
4 and 16
EXPLANATION
Let the numbers be m and n.
Since one number is four times another number, we write;
[tex]m = 4n...(1)[/tex]
The sum of the numbers is 20.
This gives us another equation:
[tex]m + n = 20...(2)[/tex]
We put equation (1) into equation (2) to obtain:
[tex]4n + n = 20[/tex]
Simplify:
[tex]5n = 20[/tex]
Divide both sides by 5.
[tex]n = 4[/tex]
We substitute n=4 into equation (1) to get;
[tex]m = 4(4) = 16[/tex]
Hence the numbers are 4 and 16.
