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Which equation is represented by the graph below?

y+1= 3/2(x-4)

y-4= 3/2(x+1)

y+4= 3/2(x-1)

y-1= 3/2 (x+4)

Which equation is represented by the graph below y1 32x4 y4 32x1 y4 32x1 y1 32 x4 class=

Respuesta :

Answer:

Step-by-step explanation:

Hello

A (5;2)

B (-1;-7)

y = ax + b

2 = 5a + b

-7 = -a + b

2 - (-7) = 5a - (-a) + b - b

2 + 7 = 5a + a

9 = 6a

a = 9/6

a = 3/2

2 = 3/2 * 5 + b

b = 2 - 15/2

b = 4/2 - 15/2

b = 11/2

y = 3/2 x + 11/2

y+1= 3/2(x-4)

y + 1 = 3/2 x - 6

y = 3/2 x - 6 - 1

y = 3/2 x - 7 => no

y-4= 3/2(x+1)

y - 4 = 3/2 x + 3/2

y = 3/2 x + 3/2 + 4

y = 3/2 x + 3/2 + 8/2

y = 3/2 x + 11/2 => yes

y+4= 3/2(x-1)

y + 4 = 3/2 x - 3/2

y = 3/2 x - 3/2 - 4

y = 3/2 x - 3/2 - 8/2

y = 3/2 x - 11/2 => no

y-1= 3/2 (x+4)

y - 1 = 3/2 x + 6

y = 3/2 x + 6 + 1

y = 3/2 x + 7 => no

xero099

Answer:

[tex]y - 1 = \frac{3}{2}\cdot (x + 4)[/tex]

Step-by-step explanation:

The function is [tex]y - 1 = \frac{3}{2}\cdot (x + 4)[/tex], since the point (1, -4) is contained in the straight line.

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