Respuesta :

sofiaSMEB22

[tex]\frac{\sqrt{8y} }{\sqrt{y} }[/tex]

Answer:

[tex]2\sqrt{2}[/tex]

I turned the numerator into an exponent: [tex]2 \frac{3}{2}[/tex]

[tex]\frac{2^{\frac{3}{2}}\sqrt{y}}{\sqrt{y}}[/tex]

The [tex]\sqrt{y}[/tex] will cancel out, leaving [tex]2 \frac{3}{2}[/tex].

[tex]2^{\frac{3}{2}}=2\sqrt{2}[/tex]

Hope this helps!!!

idkwhy14

[tex] \frac{ \sqrt{8y} }{ \sqrt{y} } = \\ [/tex]

[tex] \sqrt{ \frac{8y}{y} } = \\ [/tex]

[tex] \sqrt{8} = [/tex]

[tex] \sqrt{ {2}^{2} \times 2 } = [/tex]

[tex] \sqrt{ {2}^{2} } \sqrt{2} = [/tex]

[tex] \sqrt{4} \sqrt{2} = [/tex]

[tex]2 \sqrt{2} [/tex]

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