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A sample of gas occupies a volume of 120.0 mL at a pressure of 0.75 atm and a temperature of 295 K. What will the volume be at a pressure of 1.25 atm and a temperature of 345 K?

48 mL

4 mL

8 mL

84mL

Respuesta :

queensasha97
The answer to the question is 84
(Step By Step Explanation).
P1 V1/T1= P2 V2/T2
::0.75 x 120/295 = 1.25 x V2/345
90/295= 1.25V2/345
(cross multiply )
1.25V2 x 295 = 90 x 345
368.75V2 = 31050
(divide by the coefficient of the unknown) .
368.75V2/368.75 = 31050/368.75
V2 = 84.2. = 84
::The volume is 82.
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