Respuesta :
Answer:
(0,0).
Step-by-step explanation:
x^2 = 8y
y = 1/8 x^2
Vertex form is y = a(x - a)^2 + b where (a, b) is the coordinates of the vertex.
For this function it is y = 1/8(x - 0) + 0
so the vertex is at (0,0).
The vertex of the given parabola [tex]x^{2}[/tex] = 8y is (0,0) .
What is the vertex of a parabola ?
The vertex of a parabola is the point at the intersection of the parabola and its line of symmetry. The vertex of the parabola is the minimum point on the graph for a positive right-handed parabola.
How to find the vertex of the given parabola ?
Given parabola is [tex]x^{2}[/tex] = 8y .
∴ y = [tex]x^{2}[/tex] / 8
General vertex form for any given parabola is y = a[tex](x-a)^{2}[/tex] + b where (a, b) is the coordinates of the vertex.
For this function it is y = 1/8[tex](x - 0)^{2}[/tex] + 0
Thus the vertex of the given parabola is at (0,0).
Therefore, the vertex of the given parabola [tex]x^{2}[/tex] = 8y is (0,0) .
To learn more about vertex of parabola, refer -
https://brainly.com/question/9201543
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