A circle with center C(4,-2) contains the point D(8, 1). What is the equation of the line perpendicular to the radius of the circle passing through point C?

Respuesta :

Answer:

[tex]y + 2 = -\frac{4}{3}(x-4)[/tex]

Step-by-step explanation:

A perpendicular line is a line which has a negative reciprocal slope to the line. The slope can be found by writing the ratio between vertical and horizontal distance between the points.

[tex]m = \frac{y_2-y_1}{x_2-x_1} = \frac{1--2}{8-4}=\frac{3}{4}[/tex]

This means the slope of the perpendicular line will be -4/3.

Substitute m = -4/3 and (4,-2) into the point slope form of a linear equation.

[tex]y - -2 = -\frac{4}{3}(x - 4)\\y + 2 = -\frac{4}{3}(x-4)[/tex]

if its algebra nation, its A, y= -4/3x + 10/3 :)