Respuesta :
[tex]x^2+9x+20=0\\
x^2+4x+5x+20=0\\
x(x+4)+5(x+4)=0\\
(x+5)(x+4)=0\\
x=-5 \vee x=-4[/tex]
zeroes are when f(x)=0
0=x^2+9x+20
factor
0=(x+4)(x+5)
set each to zero
x+4=0
x=-4
x+5=0
x=-5
zeroes are f(-5) and f(-4)
0=x^2+9x+20
factor
0=(x+4)(x+5)
set each to zero
x+4=0
x=-4
x+5=0
x=-5
zeroes are f(-5) and f(-4)