Answer:
[tex]8x^3y-8x^2y-30xy=2xy(2x+3)(2x-5)[/tex]
Step-by-step explanation:
we are given an expression as
[tex]8x^3y-8x^2y-30xy[/tex]
Firstly, we will find factors
[tex](2xy)\times 4x^2-(2xy)\times 4x-(2xy)\times 15[/tex]
We can see that 2xy is common in all terms
so, we can factor out 2xy from all terms
and we get
[tex]8x^3y-8x^2y-30xy=2xy(4x^2-4x-15)[/tex]
now, we can factor again
[tex]4x^2-4x-15=(2x+3)(2x-5)[/tex]
we get
[tex]8x^3y-8x^2y-30xy=2xy(2x+3)(2x-5)[/tex]
