For this case we must find the number of miles that Shayna ran in a month.
We know he ran 6 miles in a week.
So, let "x" be the number of miles that Shayna ran in a week:
[tex]x = 6[/tex]
Let "y" be the number of miles that Shayna ran in a month, so if what she ran in a week was [tex]\frac {1} {3}[/tex] of what she ran in a month we have:
[tex]x = \frac {1} {3}y\\6 = \frac {1} {3}y\\18 = y[/tex]
So, Shayna ran 18 miles in a month
Answer:
18 miles
