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[tex]\left\{\begin{array}{ccc}x=3y+9\\9-x=-3y\end{array}\right\\\\\text{Substitute from the first equation to the second equation:}\\\\9-(3y+9)=-3y\\\\9-3y-9=-3y\\\\-3y=-3y\qquad\text{add 3y to both sides}\\\\0=0\qquad TRUE\\\\\text{Therefore you answer is}\ \boxed{infinite\ solutions}[/tex]
Answer:
infinite solutions
Step-by-step explanation:
x = 3y+9
9-x=-3y
Substitute x into the second equation
9 - (3y+9) = -3y
Distribute
9-3y-9= -3y
-3y = -3y
Add 3y to each side
-3y+3y = -3y +3y
0=0
This is a true statement always. When we always have a true statement, we have infinite solutions no matter what the variable is.
We have infinite solutions