Respuesta :

Answer:

[tex]\frac{9}{41}[/tex]

Step-by-step explanation:

given cosq = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{9}{41}[/tex]

Then qs = 9 and qr = 41

sin r = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{qs}{qr}[/tex], hence

sin r = [tex]\frac{9}{41}[/tex]


Answer:

9/41

Step-by-step explanation:

Finished the lesson and checked the answer key :DDD

I can confirm, the guy above is correct.

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