Answer:
x = 0
Step-by-step explanation:
Rewrite (6^2)^x =1 as 6^(2x) = 1.
Next, take the logarithm (common or natural) of both sides, obtaining
2x log 6 = log 1
2x log 6 = 0
Then x = 0.
Note that (6^2)^0 = 1, since any positive number raised to the prower 0 is 1.
