the equation a=1/2(b1+b2)h can be used to determine the area, a, of a trapezoid with height, h, and base lengths, b1 and b2. which are equivalent equations? check all that apply.

Answer:
b₁ = (2a – b₂h)/h; b₁ = (2a)/h – b₂; h = (2a)/(b₁ + b₂)
Step-by-step explanation:
A. Solve for b₁
a = ½(b₁ + b₂)h Multiply each side by 2
2a = (b₁ + b₂)h Remove parentheses
2a = b₁h + b₂h Subtract b₂h from each side
2a - b₂h = b₁h Divide each side by h
b₁ = (2a – b₂h)/h Remove parentheses
b₁ = (2a)/h – b₂
B. Solve for h
2a = (b₁ + b₂)h Divide each side by (b₁ + b₂)
h = (2a)/(b₁ + b₂)
Answer:
(A) and (D)
Step-by-step explanation:
It is given that the given expression [tex]a=\frac{1}{2}(b_{1}+b_{2})h[/tex]can be used to determine the area, a, of a trapezoid with height, h, and base lengths [tex]b_{1}[/tex] and [tex]b_{1}[/tex].
Thus, solving the given equation and finding the value of [tex]b_{1}[/tex], we get
[tex]a=\frac{1}{2}(b_{1}+b_{2})h[/tex]
[tex]\frac{2a}{h}-b_{2}=b_{1}[/tex]
And the expression for height is:
[tex]2a=(b_{1}+b_{2})h[/tex]
[tex]h=\frac{2a}{(b_{1}+b_{2})}[/tex]
(A) The given expression is:
[tex]\frac{2a}{h}-b_{2}=b_{1}[/tex]
which is equivalent to the given expression, therefore this option is correct.
(B) The given expression is:
[tex]\frac{a}{2h}-b_{2}=b_{1}[/tex]
which is not equivalent to the given expression, therefore this option is not correct.
(C) The given expression is:
[tex]\frac{2a-b_{2}}{h}=b_{1}[/tex]
which is not equivalent to the given expression, therefore this option is not correct.
(D) The given expression is:
[tex]\frac{2a}{b_{1}+b_{2}}=h[/tex]
which is equivalent to the given expression, therefore this option is correct.
(E) The given expression is:
[tex]\frac{a}{2(b_{1}+b_{2})}=h[/tex]
which is not equivalent to the given expression, therefore this option is not correct.