contestada

if the graph of
[tex]f(x) = \frac{9x { }^{2} + 37x + 4 }{3x + 5} [/tex]
has an oblique asymptote at y=3x+k, what is the value of k?

Respuesta :

Answer: k = 22/3

You can use polynomial long division to get the answer.

See attached image below.

Ver imagen jimthompson5910

Answer with explanation:

  [tex]f(x)=\frac{9x^2+37x+4}{3x+5}[/tex]

Since the degree in the numerator is greater than degree of Denominator .To find the Oblique asymptote we will divide numerator by denominator.

Quotient

          [tex]=3x+\frac{22}{3}[/tex]

                             --------------------------------(1)

Also, Given Oblique Asymptote

     y=3x+k-----------(2)

Now,Equating (1) and (2)

[tex]k=\frac{22}{3}[/tex]

Ver imagen Аноним

Otras preguntas