Answer:
[tex]\large\boxed{4\sqrt3\times10\sqrt{12}\times\sqrt6\times\sqrt2=480\sqrt3}[/tex]
Step-by-step explanation:
[tex]4\sqrt3\times10\sqrt{12}\times\sqrt6\times\sqrt2=(4)(10)\sqrt{(3)(12)(6)(2)}\\\\=40\sqrt{(3)(3)(2)(2)(3)(2)(2)}=40\sqrt{3^2\times2^2\times2^2\times3}\\\\\text{Use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\ \text{and}\ \sqrt{a^2}=a\ \text{for}\ a\geq0:\\\\=40\times\sqrt{3^2}\times\sqrt{2^2}\times\sqrt{2^2}\times\sqrt3=40\times3\times2\times2\times\sqrt3\\\\=480\sqrt3[/tex]
