Answer:
30.85%
Step-by-step explanation:
Assume that a set of test scores is normally distributed with a mean of 70 and a standard deviation of 10
mean = 70 and SD= 10
To find percentile we use z-score value
z value can be find using formula
[tex]z= \frac{x-mean}{SD}[/tex]
[tex]z= \frac{65-70}{10}[/tex]
z=-0.5
Now we use z- score table to find the value when z=-0.5
P(x=65) = 0.3085
To find percentile we multiply by 100
0.3085 * 100 = 30.85%
