Answer:
A. [tex]\dfrac{3}{8}[/tex] is smaller than [tex]\dfrac{1}{2}[/tex].
Step-by-step explanation:
The given fraction is [tex]\dfrac{1}{2}[/tex].
To compare two fractions, either numerator or denominator should be equal.
It is required to compare the given fraction with [tex]\dfrac{3}{8}[/tex] and [tex]\dfrac{5}{8}[/tex].
Now, the given fraction can be written as,
[tex]\dfrac{1}{2}\times\dfrac{4}{4}=\dfrac{4}{8}[/tex]
Now, the denominator of the given fraction is equal to that of other fractions.
In the fraction [tex]\dfrac{3}{8}[/tex] , numerator 3 is smaller than that of the given fraction which is 4.
So, the fraction [tex]\dfrac{3}{8}[/tex] is smaller than [tex]\dfrac{1}{2}[/tex].
In the fraction [tex]\dfrac{5}{8}[/tex] , numerator 4 is larger than that of the given fraction which is 4.
So, the fraction [tex]\dfrac{5}{8}[/tex] is larger than [tex]\dfrac{1}{2}[/tex].
Therefore, A. [tex]\dfrac{3}{8}[/tex] is smaller than [tex]\dfrac{1}{2}[/tex].
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https://brainly.com/question/20026594?referrer=searchResults
