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During a demonstration of the graviton always force on falling objects to her class , Sarah drops an 11lb bowling bowl from the top of the science building. Determine distance the ball has traveled after falling for 1.0 second, ignoring air restance and given the gravitational acceleration of 9.8m/sec^2

Respuesta :

alinakincsem

Answer:

4.9 meters

Explanation:

We know that an 11 lb bowling bowl was dropped.

So we can say that the initial speed of the bowling ball is zero ,

the time taken by the bag to free fall is given as  t = 1.0 s; and

the acceleration of free fall is given as  a = 9.8 m/s[tex]^2[/tex].

So we will use the following equation to find the distance after falling fo 1 sec:

[tex]d=v_i*t+\frac{1}{2} at^2[/tex]

Substituting the given values to get:

[tex]d=0+\frac{1}{2} * 9.8 * 1^2[/tex]

[tex]d=4.9[/tex]

Therefore, the bowling ball will cover a distance of 4.9 meters when released from the top of the building.

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