Respuesta :

Hello from MrBillDoesMath!

Answer:

(x-2)/(x-5)


Discussion:

Factor the numerator and denominator:

x^2 + x - 6 = (x+3)(x-2)

x^2-2x-15 =  (x+3)(x-5)

So  

( x^2 + x - 6) / x^2-2x-15  =   ( (x+3)(x-2) ) / ( (x+3)(x-5) )

Cancelling the (x+3) term in numerator and denominator gives

(x-2)/(x-5)


Regards,  

MrB


poona2339

(x-2)/(x-5)

A rational expression can have:

  1. any number of vertical asymptotes,
  2. only 0 or 1 horizontal asymptote,
  3. only 0 or 1 oblique (slanted) asymptote

What are the steps in solving rational expressions?

  • Solve rational equations.
  • Check for extraneous solutions.
  • Solve application problems involving rational equations.

Factor the numerator and denominator:

x^2 + x - 6 = (x+3)(x-2)

x^2-2x-15 =  (x+3)(x-5)

So  

( x^2 + x - 6) / x^2-2x-15  

= ( (x+3)(x-2) ) / ( (x+3)(x-5) )

Cancelling the (x+3) term in numerator and denominator gives

(x-2)/(x-5)

Learn more about rational expression here https://brainly.com/question/19585906

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