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Gastric acid pH can range from 1 to 4, and most of the acid is HCl.

For a sample of stomach acid that is 3.03x10^-2 M in HCl, how many moles of HCl are in 10.9 mL of the stomach acid?

Respuesta :

Chlidonias

Given the molarity of the solution is[tex]3.03*10^{-2}[/tex].

The volume of the solution is 10.9/1000 L

Number of moles of HCl = Molarity * volume of the solution in L

Number of moles of HCl =[tex]3.03*10^{-2}[/tex]*[tex]\frac{1000}{10.9}[/tex]

Number of moles of HCl = 2.7 moles.

Therefore number of moles of HCl in 10.9 ml of the stomach acid is 2.7 moles


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