Respuesta :

a1 + b (n-1)
-30 + -11 (65-1)
-30 + -11 (64)
-30+ -704
= -734

In an arithmetic sequence, the difference between one term and the next is constant.

The 65th term of the arithmetic sequence is -734

Given the following arithmetic sequence:

-30, -41, -52 The standard formula for the nth term of an arithmetic sequence is given as

a(n) = a + (n - 1)d

Where a = first term

            n = number of term

             d = common difference

Let find the common difference

Common difference = second term - first termCommon difference

= -41 - (-30)

Common difference =  -41 + 30

Common difference = -11

Common difference = -52 - (-41)

Common difference = -52 + 41

Common difference = -11

Hence, the common difference

= -11

let:

a = -30n

= 65d = -11a(65)

= -30 + (65 - 1) * -11a(65)

= -30 + (64)*-11a(65)

= -30 + (-704)a(65)

= -30 - 704a(65)

= -734

Hence, the 65th term of the arithmetic sequence is -734

Read more about arithmetic sequence at

brainly.com/question/15412619