Find the distance between the two points shown in the coordinate plane below to the nearest hundredth.

Question 16 options:

61.0


7.23


7.81


8.02

Find the distance between the two points shown in the coordinate plane below to the nearest hundredth Question 16 options 610 723 781 802 class=

Respuesta :

Answer:

7.81

Step-by-step explanation:

= √(5^2 + 6^2)

= √(25 + 36)

= √61

= 7.81

Answer:

7.81

Step-by-step explanation:

we have the points: (-2, -2) and (3, 4)

where i will call [tex]x_{1}=-2, y_{1}=-2,x_{2}=3,y_{2}=4[/tex]

We can find the distance using the Pythagorean theorem, considering that the distance in x between the points is: [tex]d_{x}=[/tex] [tex]x_{2}-x_{1}=3-(-2)=3+2=5[/tex]

and the distance in y  between the points is: [tex]d_{y}=[/tex][tex]y_{2}-y_{1}=4-(-2)=4+2=6[/tex]

and using the Pythagorean theorem

[tex]d=\sqrt{d_{x}^2 +d_{y}^2}[/tex]

[tex]d=\sqrt{5^2+6^2}=\sqrt{25+36}=\sqrt{61} =7.81[/tex]

the distance between the two points ia 7.81