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8.) Give the equation of the blue line, the red line, a line that is parallel to the red line and a line that is perpendicular to the red line.

PLEASE HELP MEE WILL GIVE BRAINLIEST AND HANGOUTS 8 Give the equation of the blue line the red line a line that is parallel to the red line and a line that is p class=

Respuesta :

Answer:

Blue line: y = -2

Red line: y = 2/3 x + 2

Perpendicular to red line: y = -3/2x + 2

Parallel to red line: y = 2/3 x + any real number



Answer:

Blue line is y=-2

Red line is [tex]y=\frac{2}{3}x+2[/tex].

Perpendicular to red is [tex]y=-\frac{3}{2}x+2[/tex].

Parallel to red is [tex]y=\frac{2}{3}x+5[/tex]

Step-by-step explanation:

The blue line is a horizontal line through the y-axis. These lines have no slope and are written as y=0x-2 since -2 is the y-intercept. We simplify and y=-2.

The red line has a slope of 2/3 since it rises 2 units for every 3 units it runs from point to point. It has a y-intercept at 2 on the y-axis. The equation in slope-intercept is y=mx +b. We substitute. [tex]y=\frac{2}{3}x+2[/tex]

To write a parallel line, we use the same slope and choose a different y-intercept. Parallel to red is [tex]y=\frac{2}{3}x+5[/tex]

To write a perpendicular line, we find the negative reciprocal of the slope which is -3/2. Perpendicular to red is [tex]y=-\frac{3}{2}x+2[/tex].